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Newton’s second law of motion formula and examples in daily life


Newton’s first law of motion

Newton’s second law of motion

Newton’s Third law of motion

According to newton’s first law of motion “if no net force is acting on a body at rest,then the body remains at rest,or if the body is moving will continue to move.”


What will happen if  net force is act on a body?

Newton perceived that velocity of a body increased or decreased by applying a net force.If the net force is applied on the side way of an object,its direction of velocity will change,which is called acceleration.This is called newton’s second law.

Newton’s second law statement

newton's second law

Newton’s second law of motion deals with situations when a net force is acting on a body.It states that:

“When a net force acts on a body,it produces acceleration in the body in the direction of the net force.The magnitude of this acceleration is directly proportional to the net force acting on the body and inversely proportional to its mass.”

Newton’s second law of motion formula

If a force produces an acceleration a in a body of mass m,then we can state mathematically that as:

a ∝ F

and  a ∝ 1/m

or     a ∝ F/m

or     F ∝ ma

Putting k as proportionality constant we get

F= kma …..(1)

In SI units ,the value of k comes out to be one.Thus equation (1) becomes:

F =ma

SI unit of force is newton (N).According to newton’s second law of motion:

“One newton (1N) is the force that produces an acceleration of 1ms-2 in a body of mass of 1 kg.Thus,a force of one newton can be expressed as:

1N = 1kg ×1ms-2

or  1N =1kgms-2

 Newton’s second law of motion examples

  • Pushing the trolley by applying force
  • Pushing or pulling the door
  • Designing the racer bike or car to increase their speed by reducing weight
  • Pulling a cart
  • Hitting a ball

Practice problems for newton’s second law of motion with answers

  1. 20 N force moves a body with an acceleration of 2m/s².What is its mass?


Force= F= 20 N

acceleration =a=2m/s.s



Formula:      F =ma

m= F/a


m=10 kg

2: How much force is needed to prevent a body of mass 10 kg from falling?


Mass= 10 kg

Gravitational acceleration =g= 10 ms‾²



F = W=mg=(10 kg)(10 ms‾²)=100 N




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